Water enters the boiler at 225°F. The boiler pressure is 100 psi and the boiler water temperature is 338°F. The latent heat is 881 Btu. What is the factor of evaporation?

FE = SH + LH / 970.3
                                FE = SH + LH / 970.3
                                FE = ((338 - 225) + 881) / 970.3 FE = 1.02
Where,
                                FE       factor of evaporation
                                SH       sensible heat
                                LH       latent heat
                                970.3 latent heat of evaporation of water at 212°F. (constant)