Water enters the boiler at 225°F. The boiler pressure is 100 psi and the boiler water temperature is 338°F. The latent heat is 881 Btu. What is the factor of evaporation?

FE = SH + LH / 970.3

                      FE = SH + LH / 970.3

                      FE = ((338 - 225) + 881) / 970.3 FE = 1.02

Where,

                      FE            factor of evaporation

                      SH            sensible heat

                      LH            latent heat

                      970.3 latent heat of evaporation of water at 212°F. (constant)